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mysql 时间排序问题

select * from 表名 order By table_id desc

-------------------------------------------方法1select * from (selecttablename_tmp.*,@rownum:=@rownum+1 ,if(time >=DATE_FORMAT(now(),'%Y-%m-%d %H:00') ,@rank:=@rank+1,@rank:=0) as rankfrom (select * from tablename order by time...

select * from table order by 时间字段 asc select * from table order by 时间字段 desc

参考mysql官方的回答: 当你的表示myisam时: SELECT * FROM tbl -- this will do a "table scan". If the table has never had any DELETEs/REPLACEs/UPDATEs, the records will happen to be in the insertion order, hence what you observed...

有两个思路 1、按照各自的活动状态先排序,插入到临时表,最后再union all所有结果集 create temporary table tmp1select * from tb where 活动状态='筹备中' order by 开始时间;create temporary table tmp2select * from tb where 活动状态='...

Mysql语句是:select * from Product as p order by p.addtime desc limit 6 Hibernate的DAO类中的语句是:from Product as p order by p.addtime desc limit 6

可以这样排序 select a.* from tblName a left join (select max(colTime) as maxtime from tblName) b on a.coltime=b.maxtime order by a.colTime desc, case when (b.maxtime is not null and a.推荐=1) then 1 else 0 end;

直接将两个字段都加入order by中即可: order by toptime desc, eidttime desc;

MySQL的date时间存储一般都建议是时间戳,存储的时候用的是int, 不建议用varchar

order by abs(month(now())-month(birthday)),abs(day(now())-day(birthday))

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