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mysql 时间排序问题

-------------------------------------------方法1select * from (selecttablename_tmp.*,@rownum:=@rownum+1 ,if(time >=DATE_FORMAT(now(),'%Y-%m-%d %H:00') ,@rank:=@rank+1,@rank:=0) as rankfrom (select * from tablename order by time...

select * from (select * from user order by date desc) as u group by u.user_id limit 0,10; 试试这个,这里表名用的是user,替换成你自己的吧。如果不是你想要的,可以加我百度hi好友,根据你的具体要求来解决。

select * from table order by 时间字段 asc select * from table order by 时间字段 desc

select * from 表名 order By table_id desc

参考mysql官方的回答: 当你的表示myisam时: SELECT * FROM tbl -- this will do a "table scan". If the table has never had any DELETEs/REPLACEs/UPDATEs, the records will happen to be in the insertion order, hence what you observed...

SELECT *FROM information_schema.TABLES WHERE table_schema='yourDB' ORDER BY create_time

Mysql语句是:select * from Product as p order by p.addtime desc limit 6 Hibernate的DAO类中的语句是:from Product as p order by p.addtime desc limit 6

直接将两个字段都加入order by中即可: order by toptime desc, eidttime desc;

有两个思路 1、按照各自的活动状态先排序,插入到临时表,最后再union all所有结果集 create temporary table tmp1select * from tb where 活动状态='筹备中' order by 开始时间;create temporary table tmp2select * from tb where 活动状态='...

根数据库系统的算法有关,早期版本的算法是自然的多个线程二分法,那个线程先查到满足条件的数据就先输出出来,这样就是乱序的,后期经过改进按照主键自然排序输出。 如果order by的值相同,一般是按自然排序,就是首个字符的字母或汉字的发音的首字...

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